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5y^2+37y-14=0
a = 5; b = 37; c = -14;
Δ = b2-4ac
Δ = 372-4·5·(-14)
Δ = 1649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{1649}}{2*5}=\frac{-37-\sqrt{1649}}{10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{1649}}{2*5}=\frac{-37+\sqrt{1649}}{10} $
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